All whole numbers except for $$1 are either prime or composite, and composite numbers can always be written as a product of primes. Finding this product (called a prime factoring) can be very useful.
A number is prime if it has exactly two factors: $$1, and itself.
A number is composite if it has more than two factors.
Learn more about prime numbers in our investigation: The Sieve of Eratosthenes.
One of the best ways to find a prime factoring is by using a factor tree. We start with the number we want to investigate, draw a box around it, and draw two lines coming out of it. Here is how we might start with the number $$12:
We then put two numbers that multiply to make $$12, such as $$4 and $$3, at the end of each of the lines:
Because $$3 is a prime number, we circle it. Since $$4 is not a prime number, we draw a box around it instead:
We then repeat the process with $$4, which is $$2×2:
And since $$2 is prime, we circle both of these numbers:
This is a completed factor tree for $$12, and it tells us that $$12=2×2×3. Multiplying the circled numbers at the end of each branch together always makes the original number.
Factor trees are not always unique - here is another factor tree for $$12:
Even though the number in the box is different, the numbers at the end of the branches will always be the same for any number - they will just be in a different order.
Here is a factor tree for $$360:
We can therefore write:
$$360=3×5×2×2×2×3
We usually rewrite the factors so they are in ascending order, like this:
$$360=2×2×2×3×3×5
We can use exponent notation to make the expression shorter as well:
$$360=23×32×5
Notice that the factor tree for $$12 we made earlier is a smaller part of the factor tree for $$360. This is because $$12 is a factor of $$360, and when we write $$360=2×2×2×3×3×5 we can recognize the prime factoring of $$12 inside it: $$360=2×(2×2×3)×3×5.
Factor trees are useful because every number we write as we make it is a factor of the original number. We don't always see every factor appear, though - for example, $$9 is a factor of $$360, but it does not appear in the tree above.
To find every factor of a number we need to combine the prime factors in every possible way. First, we find the prime factoring like we did before, such as:
$$12=2×2×3
We then combine these factors in every possible way. Every factor of $$12 can have no $$2s, one $$2, or two $$2s in its prime factoring. Similarly, every factor of $$12 can have no $$3s, or one $$3. Here we draw this out in a table:
Factors of $$12 | |||
---|---|---|---|
No $$2 | One $$2 | Two $$2s | |
No $$3 | $$1 | $$2 | $$2×2 |
One $$3 | $$3 | $$2×3 | $$2×2×3 |
We then perform each of the multiplications to find all the factors:
Factors of $$12 | |||
---|---|---|---|
No $$2 | One $$2 | Two $$2s | |
No $$3 | $$1 | $$2 | $$4 |
One $$3 | $$3 | $$6 | $$12 |
The factors of $$12 are $$1, $$2, $$3, $$4, $$6, and $$12.
Here is how we can do it for $$360 - every factor either has $$5 as a factor or it doesn't, it has between zero and two $$3s, and between zero and three $$2s.
Factors of $$360 | |||||
---|---|---|---|---|---|
No $$2 | One $$2 | Two $$2s | Three $$2s | ||
No $$5 | No $$3 | $$1 | $$2 | $$2×2 | $$2×2×2 |
One $$3 | $$3 | $$2×3 | $$2×2×3 | $$2×2×2×3 | |
Two $$3s | $$3×3 | $$2×3×3 | $$2×2×3×3 | $$2×2×2×3×3 | |
One $$5 | No $$3 | $$5 | $$2×5 | $$2×2×5 | $$2×2×2×5 |
One $$3 | $$3×5 | $$2×3×5 | $$2×2×3×5 | $$2×2×2×3×5 | |
Two $$3s | $$3×3×5 | $$2×3×3×5 | $$2×2×3×3×5 | $$2×2×2×3×3×5 |
This table shows all the possible ways to multiply the prime factors together. We evaluate the multiplications to find all the factors:
Factors of $$360 | |||||
---|---|---|---|---|---|
No $$2 | One $$2 | Two $$2s | Three $$2s | ||
No $$5 | No $$3 | $$1 | $$2 | $$4 | $$8 |
One $$3 | $$3 | $$6 | $$12 | $$24 | |
Two $$3s | $$9 | $$18 | $$36 | $$72 | |
One $$5 | No $$3 | $$5 | $$10 | $$20 | $$40 |
One $$3 | $$15 | $$30 | $$60 | $$120 | |
Two $$3s | $$45 | $$90 | $$180 | $$360 |
The factors of $$360 are $$1, $$2, $$3, $$4, $$5, $$6, $$8, $$9, $$10, $$12, $$15, $$18, $$20, $$24, $$30, $$36, $$40, $$45, $$60, $$72, $$90, $$120, $$180, and $$360.
A number has the following factor tree:
What is this number at the top of the tree?
Write $$148 as a product of its prime factors.
In this question we will be finding the factors of $$20.
First, write $$20 as a product of prime factors in expanded form.
Using your answer from part (a), list all the factors of $$20, separated by commas.