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VCE 11 General 2023

4.03 Ratios, proportion and rates

Lesson

Express and simplify ratios

A ratio compares the relationship between two or more quantities of the same type. It shows how much there is of one thing compared to another.

Suppose a train carriage has 45 people in it, of which 25 are male and 20 are female. We can express the ratio of men to women as 25:20.

A ratio can express a part-to-part relationship, as in the example above. But it can also describe a part-to-whole relationship.

For example, the ratio of males to all passengers on the train is 25:45 because there are 25 males out of the 45 people in total.

The order that the words are written in the question typically corresponds to the order of the values in the ratio.

Ratios are simplified in the same way as a fraction . A ratio is said to be in its simplest form when all terms in the ratio have a highest common factor 1.

Consider the train carriage with the ratio of men to woman as 25:20. Simplified, this would be 5:4. In other words, for every 5 males there are 4 females.

When simplifying ratios ensure any units are are written in the same unit of measure. To compare lengths 65 cm and 3 musing a ratio, it is important to convert one of the units first. In this case, write both in centimetres (65:300) before simplifying to 13:60.

Examples

Example 1

Write 32 minutes to 3 hours as a fully simplified ratio.

Worked Solution
Create a strategy

Use the fact 60 \text{ minutes} = 1 \text{ hour}.

Multiply the number of hours to minutes, and then divide the ratio by the highest common factor.

Apply the idea
\displaystyle 32:3\displaystyle =\displaystyle 32:3 \times 60Multiply 4 by 60
\displaystyle =\displaystyle 32:180Evaluate the multiplication
\displaystyle =\displaystyle \dfrac{32}{4} : \dfrac{180}{4}Divide by 4
\displaystyle =\displaystyle 8:45Simplify
Idea summary

Ratios are simplified in the same way as a fraction . A ratio is said to be in its simplest form when all terms in the ratio have a highest common factor 1.

Rates

A rate is more general than a ratio since it compares different units. A common example of a rate is speed, which is often written in kilometres per hour or km/h. You can see that this describes a relationship between two measurements-kilometres and hours. We can write this relationship as:

\text{Speed}=\dfrac{\text{Distance}}{\text{Time}} or S=\dfrac{D}{T}.

A rate describes the relationship between different units like distance to time, or cents to grams.

Examples

Example 2

If 9600 litres of water flow through a tap in 8 hours, what is the tap's flow rate per minute?

Worked Solution
Create a strategy

Use the fact 60 \text{ minutes} = 1 \text{ hour}.

Divide the number of litres by the time after converting the number of hours to minutes.

Apply the idea
\displaystyle \dfrac{9600}{8}\displaystyle =\displaystyle \dfrac{9600}{8 \times 60}Multiply 8 by 60
\displaystyle =\displaystyle \dfrac{9600}{480}Evaluate the multiplication
\displaystyle =\displaystyle 20\text{ L/min}Simplify
Idea summary

A rate describes the relationship between different units like distance to time, or cents to grams.

Proportion

When 2 rates or ratio are equal (equivalent) they are in proportion. The following ratios are in proportion:

3:5=15:25=\dfrac{1}{5}:\dfrac{1}{3}

You can use this concept of proportion to find a missing value by making equivalent ratios. If a recipe calls for 2 eggs for every 3 cups of flour, how many eggs are needed for 15 cups of flour? This can be written as:

\displaystyle 2:3\displaystyle =\displaystyle x:15Ratios are equal (in proportion)
\displaystyle \dfrac{2}{3}\displaystyle =\displaystyle \dfrac{x}{15}Expressing them as fractions
\displaystyle \dfrac{2}{3}\times 15\displaystyle =\displaystyle xMaking x the subject
\displaystyle x\displaystyle =\displaystyle 10Simplifying

You would need 10 eggs.

Alternatively, you could use equivalent fractions and make the denominators the same. In this case, multiplying the top and bottom of the left-hand-side fraction by 5 would give the same answer.

Examples

Example 3

The two quantities are in proportion. Find the missing value.

\dfrac{⬚}{10}:\dfrac{35}{50}

Worked Solution
Create a strategy

Use the fact that \dfrac{a}{b} = \dfrac{c}{d} means ad = bc.

Apply the idea

Let x be the missing value.

\displaystyle \dfrac{x}{10}\displaystyle =\displaystyle \dfrac{35}{50}Given proportion
\displaystyle \dfrac{x\times 5}{10 \times 5}\displaystyle =\displaystyle \dfrac{35}{50}Multiply the numerator and denominator on the left by 5
\displaystyle \dfrac{x\times 5}{50}\displaystyle =\displaystyle \dfrac{35}{50}Simplify
\displaystyle x\times 5\displaystyle =\displaystyle 35Equate the numerators
\displaystyle x\displaystyle =\displaystyle \dfrac{35}{5}Divide 35 by 5
\displaystyle =\displaystyle 7Evaluate

The missing value of the proportion is 7.

Idea summary

A proportion is a statement of equality between two ratios.

Divide quantities by a ratio

You may wish to divide a quantity by a given ratio.

One blue dot and 3 green dots

If we were dividing a quantity of4 items using a ratio of 1:3, it could be represented using these blue and green dots.

Here there are 4 parts in the ratio and the quantity being divided is 4. What happens if we have 40 items and we want to divide them in the ratio 1:3?

First, calculate the total number of parts in the ratio, then use it to divide the quantity into a given ratio.

The total number of parts in the (part-part) ratio is found by adding all the parts. In this case 1+3=4. Then we can divide the total quantity, which is 40 in this case by the total number of parts, which is 4, to give 10. Then using the ratio, you have a blue group of 1 \times 10 = 0 and a green group of 3 \times 10 = 30. Here we've multiple each term in the ratio by 10.

To divide a quantity by a ratio you first identify the number of parts in the ratio.

A ratio of 3:8:1 would have 12 parts in total.

Examples

Example 4

25.9 is divided into two parts, A and B, in the ratio 5:2.

a

What is the value of A?

Worked Solution
Create a strategy

Divide each side of the ratio by the total number of parts, and then multiply it to the total amount.

Apply the idea
\displaystyle A\displaystyle =\displaystyle 25.9 \times \dfrac{5}{5+2}Add the two parts
\displaystyle =\displaystyle 25.9 \times \dfrac{5}{7}Evaluate the addition
\displaystyle =\displaystyle 18.5Simplify
b

What is the value of B?

Worked Solution
Create a strategy

Divide each side of the ratio by the total number of parts, and then multiply it to the total amount.

Apply the idea
\displaystyle B\displaystyle =\displaystyle 25.9 \times \dfrac{2}{5+2}Add the two parts
\displaystyle =\displaystyle 25.9 \times \dfrac{2}{7}Evaluate the addition
\displaystyle =\displaystyle 7.4Simplify
Idea summary

The fraction method finds what fraction of the whole each side of the ratio is.

Fraction method

  • Divide each side of the ratio by the total number of parts (by adding all the numbers in the ratio)

  • Each share is worth the corresponding fraction multiplied by the total amount

The unitary method

This is a method of carrying out a calculation to find the value of a number of items by first finding the cost of one of them. This method of solving problems is often handy for solving word problems.

Examples

Example 5

Buzz bought 6 stamps for \$24.

a

What is the price for 1 stamp?

Worked Solution
Create a strategy

Divide the total cost by the number of stamps bought.

Apply the idea
\displaystyle \text{Price}\displaystyle =\displaystyle 24 \div 6Divide 24 by 6
\displaystyle =\displaystyle \$4Evaluate
b

How much would it cost him if he only wants to buy 2 stamps?

Worked Solution
Create a strategy

Multiply the price per stamp from part (a) with the number of stamps that he wants to buy.

Apply the idea
\displaystyle \text{Cost}\displaystyle =\displaystyle 4 \times 2Multiply 4 by 2
\displaystyle =\displaystyle \$8Evaluate
Idea summary

This is a method of carrying out a calculation to find the value of a number of items by first finding the cost of one of them.

Outcomes

U1.AoS2.6

concepts of ratio, proportion, percentage, percentage change and rate, and unitary method

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