The volume of a pyramid with a base area, $A$A, and height, $h$h, is given by the formula:
Volume of pyramid | $=$= | $\frac{1}{3}\times\text{area of base }\times\text{height }$13×area of base ×height |
$V$V | $=$= | $\frac{1}{3}Ah$13Ah |
The height of the prism must be perpendicular to the base when using this formula. If we are given a slant height, we'll need to use Pythagoras' theorem to work out the vertical height for the volume calculation.
Find the volume of the rectangular pyramid shown.
We wish to find the volume of the following right pyramid.
A right pyramid has a rectangular base. The base has side lengths labeled $3$3 cm along the front edge and $9$9 cm along the right side edge. From the apex of the right pyramid, a dashed line extends diagonally down the right triangular face to the midpoint of the rectangle's $9$9-cm side edge, forming the slant height of the right pyramid. The slant height of the right pyramid is labeled $14$14 cm.
First find the vertical height, correct to two decimal places.
Hence find the volume to one decimal place
A rectangular pyramid has a volume of $288$288 cm3. The base has a width of $12$12 cm and length $6$6 cm. Find the height $h$h of the pyramid.