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8.02 Circumference and area of circular shapes

Lesson

Circumference of a circle

The circumference of a circle is the distance around the edge of a circle. In other words, 'circumference' is a specific term for the perimeter of the circle.

Circumference

$$C=2πr

where $$C is the circumference, and $$r is the radius.

For example, if the radius of a circle is $$8 cm, the circumference, $$C=2πr=2×π×8=50.3 cm (rounded to one decimal place).

 

Arc of a circle

An arc of a circle is a section of the edge of a circle.

The curved side of a sector of a circle is also an arc of the circle.

 

Arc length

As the arc of a circle is a fraction of the edge of a circle, we can calculate its arc length $$s using a variation of the circumference of a circle formula.

Semicircular arc

 

Imagine first that the arc length that we want is half of the edge of the circle, then we could take half the circumference and get $$s=12×2πr

 

 

Quarter circle arc

 

What if we wanted a quarter of the edge? Then the arc length would be $$s=14×2πr

 

 

 

What if we want a different fraction? Particularly, the fraction created by using an angle $$θ. Then we would use $$s=θ3602πr.

Arc length formula

If $$θ is the angle at the centre of the circle, measured in degrees and subtended by an arc, then the arc length can be calculated using the formula:

$$s $$= $$θ360×2πr
  $$= $$r×π180×θ

 

 

The following applet helps with a visual connection between the circle, the arc and the formula. 

 

Practice questions

Question 1

Find the length of the arc in the figure correct to one decimal place.

Question 2

Find the length of the arc in the figure correct to one decimal place.

Question 3

If the arc formed by two points on a sphere with a radius of $$2m subtends an angle of $$37° at the centre, find the length of the arc correct to two decimal places.

 

 

 

Area of a circle

The area of a full circle, measured in square units, can be found using the following formula:

Area of a Circle

$$Area of a circle=πr2

 

Sectors

Given that the area of a circle is $$πr2 the area of a sector is some fraction of that full area $$θ360×πr2

There is a minor sector and a major sector associated with any given angle at the centre. The area of the corresponding sector can be found by replacing $$θ with $$360θ in the formula for the area of a sector, to become $$360θ360×πr2. Notice this simplifies to $$πr2θ360×πr2, i.e. subtracting the area of the original sector from the area of the whole circle.

$$Area=πr2

$$Area=θ360×πr2 $$Area=360θ360×πr2
$$Area=360θ360×πr2 $$Area=θ360×πr2

 

Segment

A segment is the region bounded by a chord and the arc subtended by the chord (a chord is an interval connecting two points on a circle).

The area of a minor segment is the area of a sector minus the area of a triangle.

$$Area=θ360×πr2   $$12r2sinθ   $$Area=θ360×πr212r2sinθ

Here we obtained the area of an isoceles triangle $$12r2sinθ from the formula $$Area=12absinC.

Area of a segment

For a segment which subtends an angle $$θ at the centre of a circle:

$$Area of a segment$$=$$θ360×πr212r2sinθ

Area of a major segment

To find the area of a major segment, we can just take away its corresponding minor segment from the area of the whole circle.

$$πr2   $$θ360×πr212r2sinθ   $$Area=πr2(360θ360)+12r2sinθ
Area of a major segment

For the major segment, formed from the minor segment which subtends an angle $$θ at the centre of a circle:

$$Area of major segment$$=$$360θ360×πr2+12r2sinθ

 

Practice questions 

Question 4

The diagram shows a circle with radius $$8 units, and chord $$AB subtending an angle of $$π3 radians at the centre.

Find the exact area of the minor segment cut off by chord $$AB. Fully simplify your answer.

Question 5

In the diagram, $$O is the centre of the circle, and sector $$OAB takes up $$49 of the circle.

Find the area of the minor segment cut off by chord $$AB correct to one decimal place.

Question 6

Consider a circle with centre $$O and a chord $$AB subtended by an angle of $$θ radians at the centre. The radius is $$30 cm and the area of sector $$OAB is $$75π cm2.

  1. Solve for $$θ, the angle at the centre.

  2. Find the area of the minor segment cut off by chord $$AB.

  3. Find the area of the major segment cut off by chord $$AB.

  4. Determine the exact ratio of the area of the major segment to the area of the minor segment.

 

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